(3x^2+2x^2-5x+4)/(x+2)

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Solution for (3x^2+2x^2-5x+4)/(x+2) equation: 


D( x )

x+2 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:+oo)

(3*x^2+2*x^2-(5*x)+4)/(x+2) = 0

(3*x^2+2*x^2-5*x+4)/(x+2) = 0

(5*x^2-5*x+4)/(x+2) = 0

5*x^2-5*x+4 = 0

5*x^2-5*x+4 = 0

DELTA = (-5)^2-(4*4*5)

DELTA = -55

DELTA < 0

1 = 0

1/(x+2) = 0

x belongs to the empty set

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